A 45-g piece of ice at 0 degree C is added to a sample of water at 8 degrees C. All of the ice melts and the temperature of the water decreases to 0 degree C. How many grams of water were there in the sample?

smileycellist2 2021-03-23 Answered

A 45-g piece of ice at 0 degree C is added to a sample of water at 8 degrees C. All of the ice melts and the temperature of the water decreases to 0 degree C. How many grams of water were there in the sample?

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tabuordg
Answered 2021-03-25 Author has 99 answers
Understand that once the ice melts, all you have is water at 0C. That means the water cools from 8C to 0C and the heat absorbed by the ice was enough for it to melt.
q=mass×heat of fusion the heat of fusion for water is 333J/g
q = (45 g)(333 J/g)
q = 14985 J
Now that you have the heat released by the water, use q=mcT
14985=m(4.18 JgC)(8C0C)
m=448.12 g mass of water
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