# A 45-g piece of ice at 0 degree C is added to a sample of water at 8 degrees C. All of the ice melts and the temperature of the water decreases to 0 degree C. How many grams of water were there in the sample?

A 45-g piece of ice at 0 degree C is added to a sample of water at 8 degrees C. All of the ice melts and the temperature of the water decreases to 0 degree C. How many grams of water were there in the sample?

You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

tabuordg
Understand that once the ice melts, all you have is water at ${0}^{\circ }C$. That means the water cools from ${8}^{\circ }C$ to ${0}^{\circ }C$ and the heat absorbed by the ice was enough for it to melt.
$q=\text{mass}×\text{heat of fusion}$ the heat of fusion for water is 333J/g
q = (45 g)(333 J/g)
q = 14985 J
Now that you have the heat released by the water, use $q=mc\mathrm{△}T$

m=448.12 g mass of water