A person exerts a horizontal force of 190 N in the test apparatusshown in the figure. Find the horizontal force that his flexor muscle exerts on his forearm.

net torque about the pivot = 0

\(\displaystyle{190}\cdot{0.34}-{F}\cdot{0.054}={0}\)

\(\displaystyle{F}={1196}{N}\)

net torque about the pivot = 0

\(\displaystyle{190}\cdot{0.34}-{F}\cdot{0.054}={0}\)

\(\displaystyle{F}={1196}{N}\)