The equilibrium separation of H atoms in the H2 molecule is 0.074 nm, calculate the energies and wavelengths of photons for the rotational transitions (a) L = 1 to L = 0, (b) L = 2 to L = 1, and (c) L =3 to L = 2

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Leonard Stokes · Accepted Answer

in order to find the energy differences you need to find the rotational quantity: hbar2m⋅Req2=c2hbar2Req2mc2=hc2Req24π2mc2 (1240ev⋅nm)(0.5⋅1.008u⋅931.5Mevu)(0.072nm)24π2=0.0152eV Now, the corresponding wavelengths can be found via the following equation: λ=he△E L=1→L=0△E=0.0152eVλ=81.6μm L=2→L=1△E=0.0304eVλ=40.8μm L=3→L=2△E=0.0456eVλ=27.2μm You can also note that the wavelength is halved each time atransition occurs. Accordingly, the energy is △E,2△E,3△E,etc

The equilibrium separation of H atoms in the H2 molecule is 0.074 nm, calculate the energies and wavelengths of photons for the rotational transitions (a) L = 1 to L = 0, (b) L = 2 to L = 1, and (c) L =3 to L = 2

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