A cylinder with a movable piston records a volume of 12.6L when 3.0 mol of oxygen is added. The gas in the cylinder has a pressure of 5.83 atm. The cylinder develops a leak and the volume of gas is now recorded to be 12.1 L at the same pressure. How many moles of oxygen are lost?

amanf

amanf

Answered question

2021-03-26

A cylinder with a movable piston records a volume of 12.6L when 3.0 mol of oxygen is added. The gas in the cylinder has a pressure of 5.83 atm. The cylinder develops a leak and the volume of gas is now recorded to be 12.1 L at the same pressure. How many moles of oxygen are lost?

Answer & Explanation

unett

unett

Skilled2021-03-28Added 119 answers

We know PV = nRT
thus V is directly proportional to the moles ofgas(n)
thus use the formula V1n1=V2n2
12.6L/ 3mol = 12.1L/ x mol
x=2.88mols this much moles of gas remaining
Moles of gas lost = 3mol -2.88mol
=0.12mol

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