A cylinder with a movable piston records a volume of 12.6L when 3.0 mol of oxygen is added. The gas in the cylinder has a pressure of 5.83 atm. The cylinder develops a leak and the volume of gas is now recorded to be 12.1 L at the same pressure. How many moles of oxygen are lost?

A cylinder with a movable piston records a volume of 12.6L when 3.0 mol of oxygen is added. The gas in the cylinder has a pressure of 5.83 atm. The cylinder develops a leak and the volume of gas is now recorded to be 12.1 L at the same pressure. How many moles of oxygen are lost?

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asked 2021-03-26
A cylinder with a movable piston records a volume of 12.6L when 3.0 mol of oxygen is added. The gas in the cylinder has a pressure of 5.83 atm. The cylinder develops a leak and the volume of gas is now recorded to be 12.1 L at the same pressure. How many moles of oxygen are lost?

Answers (1)

2021-03-28
We know PV = nRT
thus V is directly proportional to the moles ofgas(n)
thus use the formula \(\displaystyle\frac{{V}_{{{1}}}}{{n}_{{{1}}}}=\frac{{V}_{{{2}}}}{{n}_{{{2}}}}\)
12.6L/ 3mol = 12.1L/ x mol
x=2.88mols this much moles of gas remaining
Moles of gas lost = 3mol -2.88mol
=0.12mol
0

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