A 1004.0g sample of calcium carbonate that is 95.0% pure gives 225L of CO_{2} at STP when reacted with an excess ofhydrochloric acid. What is the density (in g/L) of the carbondioxide?

Jason Farmer

Jason Farmer

Answered question

2021-04-07

A 1004.0g sample of calcium carbonate that is 95.0% pure gives 225L of CO2 at STP when reacted with an excess ofhydrochloric acid.
What is the density (in g/L) of the carbondioxide?

Answer & Explanation

Alannej

Alannej

Skilled2021-04-09Added 104 answers

Don't gases have a molar density of 1mol/ 22.4L at STP? Can't thatbe converted to grams per liter.
Here is the long way: CaCO3+2HCI+CaCI2+CO2+H20
Thus 1004 grams of calcium carbonate only 95% pure:
grams of CaCO3:0.95(1004.0g)
Can convert that to grams of carbon dioxide:
0.95(1004.0gCaCO3)(1molCaCO3/100gCaCO3)(1molCO2/1molCaCO3)(44gCO2/1molCO2)=419.7 grams
That is 419.7 grams in 225 L, so density = 419.7g/225L = 1.87g/L

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