 # An elevator (mass 4850 kg) is to be designed so that themaximum acceleration is 0.0600g. What is the maximum and the minimum forces the motor should e Brittney Lord 2021-04-26 Answered
An elevator (mass 4850 kg) is to be designed so that themaximum acceleration is 0.0600g. What is the maximum and the minimum forces the motor should exert on the supportingcable?
I already know how to find the maximum force (just multiplyingthe maximum acceleration by the mass), but I've got no clue as tohow to find the minimum acceleration when no minimum accelerationhas been found.
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Chossing the upward direction as positive,the Maximun tension is obtained by assuming the upward accelerationas positive.
Therefore, $\mathrm{△}F=ma$
${F}_{t}-mg=ma$
Or ${F}_{t}=m\left(a+g\right)$
$=m\left(0.0600g+g\right)$
The minimum acceleration is obtained by assuming theacceleration is down.
Therefore, here ${F}_{t}=m\left(-a+g\right)$
$=m\left(-0.0600g+g\right)$