Because of its chemical similarity to calcium, 9038 Sr can collect in the bones and present a health risk. Part A What percentage of 9038 Sr present initially still exists after a period of 46.0y ? Part B What percentage of 9038 Sr present initially still exists after a period of 59.0y ? Part C What percentage of 9038 Sr present initially still exists after a period of 70.0y ?

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Nathaniel Kramer · Accepted Answer

time t=46 years Exponential behavour of the number of undecayed nuclei N=Noe−λt NNo=e−λt half life of Sr is 28.9 years decay constant λ=0.693t12 =0.69328.9 =0.0239 NNo=e−0.0239⋅46 =0.3331 =33.31% time t=59 years NNo=e−0.0239⋅59 =0.2441 =24.41% time t=70 years NNo=e−0.0239⋅70 =0.1877 =18.77%

Because of its chemical similarity to calcium, 90/38 Sr can collect in the bones and present a

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