Suppose the light bulb in the figure below is replaced with a short wire of zero resistance, and the resistance of the rails is negligible. The only resistance is from the moving rod, which is iron (resistivity =9.50×10−8 ohm.m). The rod has a cross-sectional area of 3.50×10−6m

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jlo2niT · Accepted Answer

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Jeffrey Jordon · Accepted Answer

Calculate the resistane of the rod using the following formula  R=ρLA  Here, ρ is the resistivity of the material, L is the length of the rod, and A is the area of the rod.  The induced emf in the rod due to the motion of the rod in the magnetic field is  ϵ=BLv  Here, v is the speed of the rod and B is the magnetic field.  The current in the rod is,  I=ϵR  I=BLv(pLA)  =BvAρ  Substitute the numerical values we get  I=(0.045 T)(1.0 m/s)(3.50×10−6 m2)9.50×10−8  =1.657 A  =1.66 A round off to 3 significant figure

Suppose the light bulb in the figure below is replaced with a short wire of zero resistance, and the resistance of the rails is negligible. The only resistance is from the moving rod, which is iron (resistivity =9.50\times10^{-8} ohm.m). The rod has a cross-sectional area of 3.50\times10^{-6}m

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