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A 10 henry inductor carries a steady current of 2 amp. How can a 100 volt self induced emf be made to appear in the inductor?

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asked 2021-05-18
A 10 henry inductor carries a steady current of 2 amp. How can a 100 volt self induced emf be made to appear in the inductor?

Answers (1)

2021-05-20
A (L=10H) inductor carries a steady current of (\(\displaystyle{I}_{{{r}{m}{s}}}={2}{A}\)).
How can a (\(\displaystyle{V}_{{L}}={100}\) volt) self induced emf bemade to appear in the inductor
Since:
\(\displaystyle{V}_{{L}}={I}_{{{r}{m}{s}}}\cdot{X}_{{L}}\)
\(\displaystyle{V}_{{L}}={I}_{{{r}{m}{s}}}\cdot{\left({2}\cdot?\cdot{f}\cdot{L}\right)}\)
or, \(\displaystyle{f}={\frac{{{V}_{{L}}}}{{{I}_{{{r}{m}{s}}}}}}\cdot{\left({2}\cdot?\cdot{L}\right)}\)
By connecting it to the oscillator having the frequency 'f'.
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