Question

Find the value of the CY flag after the execution ofthe following code. (a)MOV A,#85H ADD A,#92H (b) MOV A,#15H ADD A,#72H (c) MOV A,#0F5H ADD A,#52H (d)MOV A,#0FF INC A

Other
ANSWERED
asked 2021-02-28
Find the value of the CY flag after the execution ofthe following code.
(a)MOV A,#85H
ADD A,#92H
(b) MOV A,#15H
ADD A,#72H
(c) MOV A,#0F5H
ADD A,#52H
(d)MOV A,#0FF
INC A

Expert Answers (1)

2021-03-02
The Carry flag(CY) is set to 1 when there is carry from addition or borrow from substraction operation so
The Value Carry flag(CY) after the execution of given instructions is as follows
(a) CY = 1. because theresult from addition of 85H and 92H exceedesthe 8-bit.
(b) CY = 0. because thereis no carry out from addition operation.
(c) CY = 1. because there is acarry(5) from addition of F5H and 52H.
(d) CY = 0. the value ofaccumulator is FFH(255) is incrementing the value causes to resetto 0. but note that the Carry Flag is NOT set when the value "rollsover" from 255 to 0.
if you have any doubts, post the question.
49
 
Best answer

expert advice

Have a similar question?
We can deal with it in 3 hours

Relevant Questions

asked 2021-04-24
The following data fragment occurs in the middle of a datastream for which the byte-stuffing algorithm described in the textis used: A B ESC C ESC FLAG FLAG D.
What is the output after stuffing?
asked 2021-04-25
The following table lists the annual amounts of glass cullet produced by Kimble Glass Works, Inc. Year Code Scrap (tons) 1999 1 2.0 2000 2 4.0 2001 3 3.0 2002 4 5.0 2003 5 6.0 Determine the least squares trend equation. Estimate the amount of scrap for the year 2005.
asked 2021-02-25
We will now add support for register-memory ALU operations to the classic five-stage RISC pipeline. To offset this increase in complexity, all memory addressing will be restricted to register indirect (i.e., all addresses are simply a value held in a register; no offset or displacement may be added to the register value). For example, the register-memory instruction add x4, x5, (x1) means add the contents of register x5 to the contents of the memory location with address equal to the value in register x1 and put the sum in register x4. Register-register ALU operations are unchanged. The following items apply to the integer RISC pipeline:
a. List a rearranged order of the five traditional stages of the RISC pipeline that will support register-memory operations implemented exclusively by register indirect addressing.
b. Describe what new forwarding paths are needed for the rearranged pipeline by stating the source, destination, and information transferred on each needed new path.
c. For the reordered stages of the RISC pipeline, what new data hazards are created by this addressing mode? Give an instruction sequence illustrating each new hazard.
d. List all of the ways that the RISC pipeline with register-memory ALU operations can have a different instruction count for a given program than the original RISC pipeline. Give a pair of specific instruction sequences, one for the original pipeline and one for the rearranged pipeline, to illustrate each way.
Hint for (d): Give a pair of instruction sequences where the RISC pipeline has “more” instructions than the reg-mem architecture. Also give a pair of instruction sequences where the RISC pipeline has “fewer” instructions than the reg-mem architecture.
asked 2021-06-13
1. Who seems to have more variability in their shoe sizes, men or women?
a) Men
b) Women
c) Neither group show variability
d) Flag this Question
2. In general, why use the estimate of \(n-1\) rather than n in the computation of the standard deviation and variance?
a) The estimate n-1 is better because it is used for calculating the population variance and standard deviation
b) The estimate n-1 is never used to calculate the sample variance and standard deviation
c) \(n-1\) provides an unbiased estimate of the population and allows more variability when using a sample and gives a better mathematical estimate of the population
d) The estimate n-1 is better because it is use for calculation of both the population and sample variance as well as standard deviation.
\(\begin{array}{|c|c|}\hline \text{Shoe Size (in cm)} & \text{Gender (M of F)} \\ \hline 25.7 & M \\ \hline 25.4 & F \\ \hline 23.8 & F \\ \hline 25.4 & F \\ \hline 26.7 & M \\ \hline 23.8 & F \\ \hline 25.4 & F \\ \hline 25.4 & F \\ \hline 25.7 & M \\ \hline 25.7 & F \\ \hline 23.5 & F \\ \hline 23.1 & F \\ \hline 26 & M \\ \hline 23.5 & F \\ \hline 26.7 & F \\ \hline 26 & M \\ \hline 23.1 & F \\ \hline 25.1 & F \\ \hline 27 & M \\ \hline 25.4 & F \\ \hline 23.5 & F \\ \hline 23.8 & F \\ \hline 27 & M \\ \hline 25.7 & F \\ \hline \end{array}\)
\(\begin{array}{|c|c|}\hline \text{Shoe Size (in cm)} & \text{Gender (M of F)} \\ \hline 27.6 & M \\ \hline 26.9 & F \\ \hline 26 & F \\ \hline 28.4 & M \\ \hline 23.5 & F \\ \hline 27 & F \\ \hline 25.1 & F \\ \hline 28.4 & M \\ \hline 23.1 & F \\ \hline 23.8 & F \\ \hline 26 & F \\ \hline 25.4 & M \\ \hline 23.8 & F \\ \hline 24.8 & M \\ \hline 25.1 & F \\ \hline 24.8 & F \\ \hline 26 & M \\ \hline 25.4 & F \\ \hline 26 & M \\ \hline 27 & M \\ \hline 25.7 & F \\ \hline 27 & M \\ \hline 23.5 & F \\ \hline 29 & F \\ \hline \end{array}\)
...