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CoormaBak9

Answered question

2021-04-19

A high jumper, falling at 4.0m/s, lands on a foam pit andcomes to rest, compressing the pit 0.40m. If the pit is able to exert an average force of 1200N on the high jumper in breaking thefall, what is the jumper's mass?

Answer & Explanation

Sally Cresswell

Skilled2021-04-21Added 91 answers

This would be correct, only the force of gravity needs to betaken in account. I figured out the procedure:

\frac{v^{2} - v_{0}^{2}}{2 d} = a

\frac{{(0 \frac{m}{s})}^{2} - {(4.0 \frac{m}{s})}^{2}}{2 (0.40 m)}

\frac{- 16.0 \frac{m}{s^{2}}}{- 0.8 m}

20 \frac{m}{s^{2}}

=acceleration

F_{\neq t} = 1200 N - F g

and F=ma so

m a = 1200 N - m (9.8 \frac{m}{s^{2}})

m (20 \frac{m}{s^{2}}) = 1200 N - m (9.8 \frac{m}{s^{2}})

m (29 \frac{m}{s^{2}}) = 1200 N

so m=40kg

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