tinfoQ
2021-03-22
Yusuf Keller
Skilled2021-03-24Added 90 answers
distravelled by the clay and target s = 2.1m
initial velocity of clay and target be v
final velocity = 0
= 0.5
here work done by frictional force = decrease in kineticenergy of clay and target system
work done by frictional force = mgs
m = combined mass of clay and target = 100+500 = 600g =0.6kg
decrease in kinetic energy of clay and target system
therefore
plug the values and solve for v
v=(2gs)=4.53m/s
let velocity of clay before impact be u
mass of clay m1 = 100g = 0.1kg
Then initial momentum of clay = (m1)u = 0.1*u
final momentum of clay and target system
in any collision momentum is conserved
then initial momebtum = final momentum
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