The arm weighs 44.0 N. The force of gravity acting on the arm acts through point A. Determine the magnitudes of the tension force t in the deltoid muscle and the force s of the shoulder on the humerus (upper-arm bone) to hold the arm in the position shown. t=N s=N

preprekomW

preprekomW

Answered question

2021-04-21

The arm weighs 44.0 N. The force of gravity acting on the arm acts through point A. Determine the magnitudes of the tension force t in the deltoid muscle and the force s of the shoulder on the humerus (upper-arm bone) to hold the arm in the position shown.
t=N
s=N

Answer & Explanation

unett

unett

Skilled2021-04-23Added 119 answers

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Jeffrey Jordon

Jeffrey Jordon

Expert2021-09-29Added 2605 answers

Weight of the arm Fg=44.0 N

τ=0

(Fy)(0.08 m)(Fg)(0.290 m)=0

(Ftsin12)(0.08 m)(Fg)(0.290 m)=0

Ft=(44.0 N)(0.290 m)(0.08)(sin12)=768.6 N769 N

Ft=t=769 N

Fx=0

FxFtcos12=0

Fx=Ftcos12

Fx=(769 N)cos12

=752.19 N

Fy=0

Ftsin12Fy44.0 N=0

Fy=44.0 N+Ftsin12116 N

Fs=s=Fx2+Fy2=(759.19 N)2+(116 N)2=761 N

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