The arm weighs 44.0 N. The force of gravity acting on the arm acts through point A. Determine the magnitudes of the tension force t in the deltoid muscle and the force s of the shoulder on the humerus (upper-arm bone) to hold the arm in the position shown. t=N s=N

preprekomW 2021-04-21 Answered
The arm weighs 44.0 N. The force of gravity acting on the arm acts through point A. Determine the magnitudes of the tension force t in the deltoid muscle and the force s of the shoulder on the humerus (upper-arm bone) to hold the arm in the position shown.
t=N
s=N
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Expert Answer

unett
Answered 2021-04-23 Author has 119 answers
Jeffrey Jordon
Answered 2021-09-29 Author has 2047 answers

Weight of the arm Fg=44.0 N

Applying equlibrium conditions τ=0

(Fy)(0.08 m)(Fg)(0.290 m)=0

(Ftsin12)(0.08 m)(Fg)(0.290 m)=0

Ft=(44.0 N)(0.290 m)(0.08)(sin12)

=768.6 N

769 N

Magnitude of tension force

Ft=t=769 N

Now apply the first conditions of equlibtium

Along xaxis

Fx=0

FxFtcos12=0

Fx=Ftcos12

Fx=(769 N)cos12

=752.19 N

Along y axis

Fy=0

Ftsin12Fy44.0 N=0

Fy=44.0 N+Ftsin12

116 N

So the force F, extered by the shoulder. On the humerces to hold the arms in the position

Fs=s=Fx2+Fy2

=(759.19 N)2+(116 N)2

=761 N

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