Water is being boiled in an open kettle that has a 0.500-cm-thick circular aluminum bottle with a radius of 12.0cm. If the water boils away at a rate

smileycellist2

smileycellist2

Answered question

2021-03-27

Water is being boiled in an open kettle that has a 0.500-cm-thick circular aluminum bottle with a radius of 12.0cm. If the water boils away at a rate of 0.500 kg/min,what is the temperature of the lower surface of the bottom of the kettle? Assume that the top surface of the bottom of the kettle is at 100 C.

Answer & Explanation

lobeflepnoumni

lobeflepnoumni

Skilled2021-03-29Added 99 answers

Water is being boiled in an open kettlethat has a (L = 0.500-cm) -thick circular aluminum bottle with a radius of (r = 12.0cm).
If the water boils away at a rate of
dmdt=0.500 kgmin=8.33103 kgs
Let the temperature of the lower surface of the bottom of thekettle be t2 C
The temperature of thetop surface of the bottom of the kettle (t1=100C)
Since the heat given by the aluminium bottle = heattaken by boiled water
kA(t2t1)dtL)=dmLs
Where
K=238 Js
A=pr2
dt=time taken for the mass dm
Latent Heat of steam (Ls)=2256000 J/kg
Ahain from above equation
kAt2t1d=dmdtLs
Now calculate the value of t2 from above

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