A spring is mounted vertically on the floor. The mass of the spring is negligible. A certain object is placed on the spring to compress it. When the object is pushed further down by just a bit and then released, one up/down oscillation cycle occurs in 0.250 s. However, when the object is pushed down by 5.00×10−2 m to point P and then released, the object flies entirely off the spring. To what height above point P does the object rise in the absence of air resistance?

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sweererlirumeX · Accepted Answer

Potential stored in the spring is utilised to give kineticenergy to object 12kx2=12mv2 Therefore kmx=v but k/m =angular speed =2/Time period=2/0.25 = 8 =25rad/s x = distance of compression =5.00×10−2 m plug the values we get v this kinetic energy is sufficient to raise to a height h mgh=12mv2 then h=v22g g=9.8ms2 plug the value of v and g we get height

A spring is mounted vertically on the floor. The mass of the spring is negligible. A certain object is placed on the spring to compress it. When the o

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