A floating ice block is pushed through a displacement d=(15m)i-(12m)j along a straight embankment by rushing water, which exerts a force F=(210N)i-(150N)j on the block. How much work does theforce do on the block during the displacement?

ruigE 2021-03-21 Answered
A floating ice block is pushed through a displacement d=(15m)i-(12m)j along a straight embankment by rushing water, which exerts a force F=(210N)i-(150N)j on the block. How much work does theforce do on the block during the displacement?
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Expert Answer

Jozlyn
Answered 2021-03-23 Author has 85 answers
The work done W = F.d
=(210i150j)(15i12j)
=3150i1800j
Thus, magnitude of the work done W=(Fx2+Fy2)12
Or W=3.63103 J
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Jeffrey Jordon
Answered 2021-10-14 Author has 2064 answers

Solution

We find the work done by the water on the ice block: 

W=Fd

=[(210N)i^(150N)j^][(15m)i^(12m)j^]

=(210 N)(15 m)+(-150 N)(-12 m)

=5.0×103 J

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