A 5 kg uniform square plate is supported by two identical 1.5kg uniform slender rods AD and BE and is released from rest inthepostion theta 45 degrees. Knowing that the angular velocity ofAD as it passes through the vertical position is 5.2 rad/sdetermine the amount of energy dissipated infriction.
Bevan Mcdonald
Answered question
2021-04-04
Answer & Explanation
Isma Jimenez
Skilled2021-04-06Added 84 answers
To do this you must find the height using trigonometry
Since energy is conserved the kinetic energy at the bottom of thependulum must equal the potential at the top minus the energydissipated.
So energy dissipated =PE-KE=0.05078 J
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