Four polarizers are placed in succession with their axesvertical, at 30 degrees to the vertical, and at 60 degrees to thevertical, and at 90degrees to

sodni3

sodni3

Answered question

2021-03-10

Four polarizers are placed in succession with their axesvertical, at 30 degrees to the vertical, and at 60 degrees to thevertical, and at 90degrees to the vertical.
A. calculate what fraction of the incident unpolarizedlight is transmitted by the four polarizers.
B. Can the transmitted light be decreased by removingone of the polarizers? If so, which one?
C. Can the transmitted light intensity be extingusishedby removing one of the polarizers? If so, which one(s)?

Answer & Explanation

SabadisO

SabadisO

Skilled2021-03-12Added 108 answers

A) The intensity of the light passing through thesuccessive polarizers is
I1=(12)Io
I2=I1cos2θ2
=(12)Iocos2θ2
I3=I2cos2θ3
(12)Iocos2θ2cos2θ3
I4=I3cosθ4
=(12)Iocos2θ2cos2θ3cos2θ4
(12)Iocos230cos230cos230
=0.21Io
B) If we remove the second polarizer we get
I1=(12)Io
I3=I1cos2θ3
=(12)Iocos2θ3
I4=I3cos2θ4
(12)Iocos2θ3cos2θ4
(12)Iocos260cos230
=0.094Io
Thus we can decrease the intensity byremoving the second or third polarizer.
C) If we remove the second and thirdpolarizers we will have two polarizers with their axesperpendicular to each other and so no light willbe transmitted.

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