First lets put the two distances the cable will cover in terms of x:

The length on the ground is 2 miles minus x. to find c weneed to use the pythagorean theorem:

\(\displaystyle{800}^{{2}}+{x}^{{2}}={c}^{{2}}\)

\(\displaystyle{c}=\sqrt{{{800}^{{2}}-{x}^{{2}}}}\)

now we have all the information we need to make a costfunction:

\(\displaystyle{C}{\left({x}\right)}={180}\sqrt{{{800}^{{2}}-{x}^{{2}}}}+{100}{\left({10560}-{x}\right)}\)

b) use point plotting to answer b

The length on the ground is 2 miles minus x. to find c weneed to use the pythagorean theorem:

\(\displaystyle{800}^{{2}}+{x}^{{2}}={c}^{{2}}\)

\(\displaystyle{c}=\sqrt{{{800}^{{2}}-{x}^{{2}}}}\)

now we have all the information we need to make a costfunction:

\(\displaystyle{C}{\left({x}\right)}={180}\sqrt{{{800}^{{2}}-{x}^{{2}}}}+{100}{\left({10560}-{x}\right)}\)

b) use point plotting to answer b