In the overhead view of, a long uniform rod of mass m0.6 Kg is free to rotate in a horizontal planeabout a vertical axis through its center .A spring with force constant k = 1850 N/m is connected horizontally betweenone end of the rod and a fixed wall. When the rod is in equilibrium, it is parallel to the wall. What isthe period of the small oscillations thatresult when the rod is rotated slightly and released?

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In the overhead view of, a long uniform rod with mass (m = 0.6 kg) is free to rotate along a vertical axis that runs through its center in a horizontal plane.A horizontal spring connection is made between one end of the rod and a fixed wall with a force constant of k = 1850 N/m.The rod is parallel to the wall when it is in an equilibrium state.Let T represent the duration of the minute oscillations that occur when the rod is spun and then released.Let rod ( length L) rotates by angle (θ)If &quot;F&quot; is the force exerted on the rod, the spring will extend by that amount.&amp;nbsp;(△x)=Lθ2Since , the moment of force&amp;nbsp;(τ)=−FL2Or&amp;nbsp;(τ=−FL2=−kLθ2⋅L2&amp;nbsp;=−kL24⋅θSo, the time period&amp;nbsp;(T)=2π⋅lCwhere&amp;nbsp;I=mL212C=kL24So,&amp;nbsp;T=2π⋅m3kHere m=0.6 kg and k=1850 N/mT=0.06533s

In the overhead view of, a long uniform rod of mass m0.6 Kg is free to rotate in a horizontal planeabout a vertical axis through its center .A spring

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