Expert Answer to "A 2.0-kg projectile is fired with initial velocity..."

sodni3

Answered question

2021-04-18

A 2.0-kg projectile is fired with initial velocity components $v_{0 x} = 30$ m/s and $v_{0 y} = 40$ m/s from a point on the earth's surface. Neglect any effects due to air resistance. What is the kinetic energy of the projectile when it reaches the highest point in its trajectory? How much work was done in firing the projectile?

Answer & Explanation

Arnold Odonnell

Skilled2021-04-20Added 109 answers

A 2.0-kg projectile is fired with initialvelocity components $v_{0 x} = 30$ m/s and $v_{0 y} = 40$ m/s from a point on the earth's surface. Neglect any effects dueto air resistance.
$v^{2} = {(v_{0 x})}^{2} + {(v_{0 x})}^{2}$
$v = 50.0 \frac{m}{s}$
Angle for projectile (q)
$V_{0 x} = v \cos (q)$
$(q) = {53.13}^{\circ}$
The height attained by the object $(h) = \frac{{[V \cdot \sin (q)]}^{2}}{2 g}$
$= 81.63 m$
The kinetic energy of the projectile when it reaches thehighest point in its trajectory is equal to the potential energy
$K . E = m g h$
$= 1600 J$
The work-done infiring the projectile $= 1600 J$

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Force, Motion and Energy

Didn't find what you were looking for?