Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of K=3.60. The resultant electric field in the dielectric is 1.20×106 volts per meter. Compute the magnitude of the charge per unit area σ on the conducting plate. σ=cm2 Compute the magnitude of the charge per unit area σ1 on the surfaces of the dielectric. σ1=cm2 Find the total electric-field energy U stored in the capacitor. u=J

Question

Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of K=3.60. The resultant electric field in the dielectric is 1.20×106 volts per meter.  Compute the magnitude of the charge per unit area σ on the conducting plate.  σ=cm2  Compute the magnitude of the charge per unit area σ1 on the surfaces of the dielectric.  σ1=cm2  Find the total electric-field energy U stored in the capacitor.  u=J

Malena · Accepted Answer

a) the magnitude of the charge per unit area σ on the conducting plate:  E effective=σkϵ0  σ=3.6⋅8.854e−12⋅1.20e6=3.82⋅e−5Cm2  b) The magnitude of the charge per unit area σ1 on the surfaces of the dielectric.  σ (on the dielectric) =σ((1k)−1)  =−2.75e−5 Cm2

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Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick,

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