Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick,

generals336 2021-04-30 Answered
Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of K=3.60. The resultant electric field in the dielectric is 1.20×106 volts per meter.
Compute the magnitude of the charge per unit area σ on the conducting plate.
σ=cm2
Compute the magnitude of the charge per unit area σ1 on the surfaces of the dielectric.
σ1=cm2
Find the total electric-field energy U stored in the capacitor.
u=J
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Expert Answer

Malena
Answered 2021-05-02 Author has 83 answers
a) the magnitude of the charge per unit area σ on the conducting plate:
E effective=σkϵ0
σ=3.68.854e121.20e6=3.82e5Cm2
b) The magnitude of the charge per unit area σ1 on the surfaces of the dielectric.
σ (on the dielectric) =σ((1k)1)
=2.75e5 Cm2
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