Compute the magnitude of the charge per unit area

Compute the magnitude of the charge per unit area

Find the total electric-field energy U stored in the capacitor.

u=J

generals336
2021-04-30
Answered

Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of K=3.60. The resultant electric field in the dielectric is $1.20\times {10}^{6}$ volts per meter.

Compute the magnitude of the charge per unit area$\sigma$ on the conducting plate.

$\sigma =\frac{c}{{m}^{2}}$

Compute the magnitude of the charge per unit area$\sigma}_{1$ on the surfaces of the dielectric.

$\sigma}_{1}=\frac{c}{{m}^{2}$

Find the total electric-field energy U stored in the capacitor.

u=J

Compute the magnitude of the charge per unit area

Compute the magnitude of the charge per unit area

Find the total electric-field energy U stored in the capacitor.

u=J

You can still ask an expert for help

Malena

Answered 2021-05-02
Author has **83** answers

a) the magnitude of the charge per unit area $\sigma$ on the conducting plate:

E effective=$\frac{\sigma}{k{\u03f5}_{0}}$

$\sigma =3.6\cdot 8.854{e}^{-12}\cdot 1.20{e}^{6}=3.82\cdot {e}^{-5}\frac{C}{{m}^{2}}$

b) The magnitude of the charge per unit area σ1 on the surfaces of the dielectric.

$\sigma$ (on the dielectric) $=\sigma (\left(\frac{1}{k}\right)-1)$

$=-2.75{e}^{-5}\text{}\frac{C}{{m}^{2}}$

E effective=

b) The magnitude of the charge per unit area σ1 on the surfaces of the dielectric.

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