Boom AB is held in the position shown by three cables. Knowing that the tensions in calbe AC and AC are 900lb and 1200lb,respectively, determne (a) th

djeljenike

djeljenike

Answered question

2021-02-23

Boom AB is held in the position shown by three cables. Knowing that the tensions in calbe AC and AC are 900lb and 1200lb,respectively, determne (a) the tension in cable AE if the resultant of thettensions exerted at point A of the boom must be directed along AB, (b) the corresponding magnitude o the resultant.

Answer & Explanation

avortarF

avortarF

Skilled2021-02-25Added 113 answers

Fx Tension=R=AE
ACx=900lbs
ADx=12000cos(30)=1039.23lbs
AEx=Rcos(50)
Fy
ACy=0
ADy=600lbs
AEy=Rsin(50)
ACx+ADx=1939.23lbs
ACy+ADy=600lbs
Just solve the following equations for R and P...
19.39.23Rcos(50)=Pcos(65)
600Rsin(50)=Psin(65)
You should get...
R=1659.45lbs
P=2064.65lbs

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