Individual A has a red die and B has a green die (both fair).If they each roll until they obtain five "doubles" (1-1,....,6-6),what is the pmf of X= the total number of times a die is rolled?What are E(X) and V(X)?

foass77W

foass77W

Answered question

2021-04-25

Individual A has a red die and B has a green die (both fair).If they each roll until they obtain five "doubles" (1-1,....,6-6),what is the pmf of X= the total number of times a die is rolled?What are E(X) and V(X)?

Answer & Explanation

Jayden-James Duffy

Jayden-James Duffy

Skilled2021-04-27Added 91 answers

Here is the solution:

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Jeffrey Jordon

Jeffrey Jordon

Expert2021-09-08Added 2605 answers

Probability of getting double is 16×16=136

Now let X be a random variable equal to total number of times dies rolled until they obtain five doubles

Where A and B are throwing simultaneously and both dice are fair so here the total number of rolls are 10 to obtain 5 doubles.

So the last roll must be success

pmf of X=P {9 sucesses in first (x-1) rolls} * P{last roll is success}

P(x)=(x+99)(16)9(56)x1×56

Mean=E(X)=r(1p)p

=100(116)16

V(X)=r(1p)p2

=10(116)16×16

=300

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