Variation of the rate constant with temperature for the first-order reaction

Variation of the rate constant with temperature for the first-order reaction

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asked 2021-03-11

Variation of the rate constant with temperature for the first-order reaction:
\(\displaystyle{2}{N}_{{2}}{O}_{{5}}{\left({g}\right)}\to{2}{N}_{{2}}{O}_{{4}}{\left({g}\right)}+{O}_{{2}}{\left({g}\right)}\)
is given in the following table. Determine graphically the activation energy for the reaction.
\(\begin{array}{|l|l|}\hline T(K)&K(s^{-1})\\\hline298&1.74\cdot10^{-5}\\\hline308&6.61\cdot10^{-5}\\\hline318&2.51\cdot10^{-4}\\\hline328&7.59\cdot10^{-4}\\\hline338&2.40\cdot10^{-3}\\\hline\end{array}\)

Answers (1)

2021-03-13

Plot a graph of lnk vs \(\displaystyle{\frac{{{1}}}{{{T}}}}\) with the help ofdata given such that u get a slope which is equal to \(\displaystyle{\frac{{-{E}_{{a}}}}{{{R}}}}\)
Then plot a graph like this:
image
according to the equation
\(\displaystyle{\ln{{k}}}={\left({\frac{{-{E}_{{a}}}}{{{R}}}}\right)}{\left({\frac{{{1}}}{{{T}}}}\right)}+{\ln{{A}}}\)
sloope \(\displaystyle={\left({\frac{{-{E}_{{a}}}}{{{R}}}}\right)}\)
\(\displaystyle{E}_{{a}}=\) -slope \(\cdot R\)

0

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