# The spring in the figure (a) is compressed by length delta x . It launches the block across a frictionless surface with speed v0. The two springs in t

The spring in the figure (a) is compressed by length delta x . It launches the block across a frictionless surface with speed v0. The two springs in the figure (b) are identical to the spring of the figure (a). They are compressed by the same length delta x and used to launch the same block. What is the block's speed now?
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Nathanael Webber
The energy stored in the spring is $0.5\cdot k\cdot \mathrm{△}{x}^{2}$ this must equal the kinetic energy of the released block.
$0.5\cdot m\cdot {v}_{0}^{2}=0.5\cdot k\cdot \mathrm{△}{x}^{2}$
${v}_{0}=\mathrm{△}x\cdot x\sqrt{\frac{2\cdot k}{m}}$
The speed from two springs is $\sqrt{2}$ times the speed with one spring.