A square loop of copper wire is initially placed perpendiclar to the lines of a constant magnetic field of&nbsp;5×103&nbsp;T.The area enclosed by the loop is 0.2 square meter. the loopis then turned through an angle&nbsp;90∘&nbsp;so thatthe plane of the loop is parallel to the field lines. the turntakes 0.1 second. What is the typical emf generated during the turn in the loop?

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A square loop of copper wire is initially placed perpendiclar to the lines of a constant magnetic field of&amp;nbsp;5×103&amp;nbsp;T.The area enclosed by the loop is 0.2 square meter. the loopis then turned through an angle&amp;nbsp;90∘&amp;nbsp;so thatthe plane of the loop is parallel to the field lines. the turntakes 0.1 second. What is the typical emf generated during the turn in the loop?

yagombyeR · Accepted Answer

Eavg=−N△ϕ△tN is number of turns of loop = 1△ϕ is change of flux linked with the loop△t is time in which the change of flux has taken placeϕ=BA=5×103×0.2=1×103 when plane of loop is perpendicular tofield ϕ=0 when the plane of loop is parallel to field.E=1×1030.1=1×104 vThe negative sign in formula simply shows the direction of induced emf is such that it opposes the change influx according to Lenz&#039;s Law.

A square loop of copper wire is initially placed perpendiclar to the lines of a constant magnetic field of 5\times10^3 T.The area enclosed by the loop

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