A single constant force F= (3i+5j) N acts ona 4.00-kg particle.

sodni3

sodni3

Answered question

2020-10-23

A single constant force F=(3i+5j) N acts ona 4.00-kg particle. (a) Calculate the work done by this forceif the particle moves from the origin to the point having the vector position r=(2i3j)m. Does thisresult depend on the path? Explain. (b) What is the speed ofthe particle at r if its speed at the origin is 4.00 m/s? (c) What is the change in the potential energy?

Answer & Explanation

broliY

broliY

Skilled2020-10-24Added 97 answers

Force is given as F=(3i+5j)N mass=4kg
a) workdone =F.ds=(3i+5j).(2i3j)=615=9J
the work done is path independant since we did not considerany frictional force.
b) speed at r if speed at origin is 4 m/s
we can calculate acceleration a=|F|m=?32+524=1.46ms2
we can use v2=u2+2as with s beings =?(22+32)=3.6m
v2=42+2(1.46)(3.6)
solve for v
c)You can use energy conservation to get this part

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