A hollow sphere of inner radius 8.0cm and outer radius 9.0cmfloats half -submerged in a liquid of density 800 kgm3 (a) What is the mass of the sphere? (b) calculate the density of the material of which the sphere is made.

Vsphere=43π (.09)3−43π (.08)3==9.09x104 m3Vwater=43π(.09)32 =1.53x103m Mwater=1.53×10−3(800)=1.2kg Msphere=1.2kg MV=1.29.09×10−4=1.3×103

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Cheyanne Leigh

2021-02-23

A hollow sphere of inner radius 8.0cm and outer radius 9.0cmfloats half -submerged in a liquid of density 800

k \frac{g}{m^{3}}

(a) What is the mass of the sphere? (b) calculate the density of the material of which the sphere is made.

SoosteethicU

Skilled2021-02-24Added 102 answers

V_{s p h e r e} = \frac{4}{3} π

{(.09)}^{3} - \frac{4}{3} π

{(.08)}^{3} == 9.09 x 10^{4}

m^{3} V_{w a t e r} = \frac{\frac{4}{3} π {(.09)}^{3}}{2}

= 1.53 x 10^{3} m

M_{w a t e r} = 1.53 \times 10^{- 3} (800) = 1.2 k g

M_{s p h e r e} = 1.2 k g

\frac{M}{V} = \frac{1.2}{9.09 \times 10^{- 4}} = 1.3 \times 10^{3}

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