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Consider a hypothetical 32-bit microprocessor having32-bit instructions composed of two fields: the first byte containsthe opcode and the remainder th

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asked 2020-11-10
Consider a hypothetical 32-bit microprocessor having32-bit instructions composed of two fields: the first byte containsthe opcode and the remainder the immediate operand or an operandaddress.
What is the maximum directly addressable memory capacity(in bytes)?
Discuss the impact on the system speed if themicroprocessor bus has:
a32-bit local address bus and a 16-bit local data bus, or
a16-bit local address bus and a 16-bit local data bus.
How many bits are needed for the program counter and the instruction register ?

Answers (1)

2020-11-11
Consider a hypothetical 32-bit microprocessor having32-bit instructions composed of two fields: the first byte containsthe opcode and the remainder the immediate operand or an operandaddress.
What is the maximum directly addressable memory capacity(in bytes)?
since there 1 byte of 16 bits left to address theRAM the maximum number of memory locations that can be addressed is \(\displaystyle{2}^{{{16}}}\)
Discuss the impact on the system speed if the microprocessor bus has:
a32-bit local address bus and a 16-bit local data bus, here systemspeed is faster than
a16-bit local address bus and a 16-bit local data bus.
as in the former case larger memory is directly accessible
How many bits are needed for the program counter and the instruction register ?
16 bits for each the program counter and theinstruction register .
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