For tests using a ballistocardiograph, a patient lies on a horizontal platform that is supported on jets of air. Because of the air jets, the friction

Phoebe 2021-01-31 Answered
For tests using a ballistocardiograph, a patient lies on a horizontal platform that is supported on jets of air. Because of the air jets, the friction impeding the horizontal motion of the platform is negligible. Each time the heart beats, blood is pushed out of the heart in a direction that is nearly parallel to the platform. Since momentum must be conserved, the body and the platform recoil, and this recoil can be detected to provide information about the heart. For each beat, suppose that 0.050 kg of blood is pushed out of the heart with a velocity of +0.30 m/s and that the mass of the patient and the platform is 85 kg. Assuming that the patient does not slip with respect to the platform, and that the patient and the platform start from rest, determine the recoil velocity.
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Expert Answer

tabuordg
Answered 2021-02-01 Author has 99 answers
given for blood mass m1=0.050 kg
initial velocity vo1+0.30 ms
final velocity vf1=0 ms
for man mass m2=80 kg
initial velocity is vo2 final velocity vf2=0 ms
applying principle of conservation of linear momentum we have
m1v01+m2v02=m1vf1+m2vf2
Or vo2=(m1m2)vo1
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