\(\displaystyle{5.66}\times{10}^{{5}}\ {f}{t}^{{2}}\cdot{\frac{{{0.0929}\ {m}^{{2}}}}{{{1}\ {f}{t}^{{2}}}}}={5.26}\times{10}^{{4}}\ {m}^{{2}}\)

\(\displaystyle{481}{f}{t}\cdot{\frac{{{0.3048}}}{{{1}{f}{t}}}}={147}{m}\)

\(\displaystyle{V}={\frac{{{\left({5.26}\times{10}^{{4}}{m}^{{2}}{\left({147}{m}\right)}\right\rbrace}{\left\lbrace{3}\right\rbrace}={2.58}\times{10}^{{6}}{m}^{{3}}}}{}}\)