1. The centripetal acceleration is

a = r?2 = (0.14)(2?*1.7)2 =15.9729m/s^2

2. Given that

The radius(r)=10cm=0.10m

The angular valocity isrevolutions/sec

The centripetal acceleration is substitute the above given values you get the required answer

3. Radius of the container R =14cm

Angular velocity of the cylinder w= 1.7rev/s

Centripetal accelearation a = Rw2

4. The equation for centripetal acceleration is a = v^2/R; where v is velocity and R is radius. The equation for velocity is change in X (position) divided by the change in time, t. The change of position during a circle motion is 2(PI)R times #of Revolutions all divided by time, t. So v = (2(3.14)(0.11m)(2.4)/1sec Place this velocity in the equation for centripetal acceleration (v^2/R) and you should get an answer of [6.25 m/sec^2].

a = r?2 = (0.14)(2?*1.7)2 =15.9729m/s^2

2. Given that

The radius(r)=10cm=0.10m

The angular valocity isrevolutions/sec

The centripetal acceleration is substitute the above given values you get the required answer

3. Radius of the container R =14cm

Angular velocity of the cylinder w= 1.7rev/s

Centripetal accelearation a = Rw2

4. The equation for centripetal acceleration is a = v^2/R; where v is velocity and R is radius. The equation for velocity is change in X (position) divided by the change in time, t. The change of position during a circle motion is 2(PI)R times #of Revolutions all divided by time, t. So v = (2(3.14)(0.11m)(2.4)/1sec Place this velocity in the equation for centripetal acceleration (v^2/R) and you should get an answer of [6.25 m/sec^2].