Question

A basket of negligible weight hangs from a vertical springscale of force constant 1500 N%2Fm. If you suddenly put an adobe brick of mass 3.00 kg in th

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Solve for the distance $$\displaystyle{y}_{{{f}}}$$ the spring will stretch.
force in the spring is F=kx the force in the spring is opposite of the force that isexerted gravity on the brick so Force in spring= massofbrickX accelerationof gravity= 29.43Newtons 29.43 Newtons=1500 N/m*X so X(displacement of spring)= $$\displaystyle{\frac{{{29.43}}}{{{1500}}}}={19.62}{m}{m}$$