A morsel of food with a mass of 4.2 g is injected into theesophagus with an initial speed of 2.5cm/s. On the way down to thestomach, the walls of the esophagus exert an upward resistive forceof 2.7×10−3N on the morsel. If the esophagus is 20.0 cm long,with what speed does the morsel of food enter the stomach? I need some help setting this problem up.

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Asma Vang · Accepted Answer

We are aware that the work (W) a constant force performs on an object is iWnc=(KE+PEg)f−(KE+PEg)is defined as theproduct of the component of the force along the directionof displacement and the magnitude of displacement&amp;nbsp;W=(Fcos?)?xSimilarly the work (Wnc) done by the non-consrvative resistance force willbe&amp;nbsp;Wnc=(Fcos?)?x&amp;nbsp;in our problem&amp;nbsp;?=180∘F=2.7×10−3N?x=0.20mWnc=−5.4×10−4JTo find the speed we usethe work energy theorm from which we can write&amp;nbsp;Wnc=(KE+PEg)f−(KE+PEg)iKEf=Wnc+KEi+(PEg)i−(PEg)fSo,12mvf2=Wnc+12mvi2+mg(yi−yf)yi−yf=0.2mSolvefor v fit will come as&amp;nbsp;1.9m/s

A morsel of food with a mass of 4.2 g is injected into theesophagus with an initial speed of 2.5 cm/s. On the way down to thestomach, the walls of the

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