A bowler throws a bowling ball of radius R=11cm along a lane. Theball, slides on the lane with initial speed of v = 8.5 m/s andangular speed omega = 0

geduiwelh

geduiwelh

Answered question

2021-01-31

A bowler throws a bowling ball of radius R=11cm along a lane. Theball, slides on the lane with initial speed of v=8.5 m/s andangular speed ω=0. The coefficient of kinetic frictionbetween the ball and the lane is 0.21. The kinetic frictional forcef acting on the ball causes a linear acceleration of the ball whileproducing a torque that causes an angular acceleration of the ball.When the speed v has decreased enough and angular speed omega hasincreased enough, the ball stops sliding and then rollssmoothly.
a) What is v in terms of omega?
b) During the sliding, what are the ball's linear accelerationand
c) angular acceleration?
d) How long does the ball slide?
e) How far does the ball slide?
f) What is the linear speed of the ball when smooth rollingbegins?

Answer & Explanation

Anonym

Anonym

Skilled2021-02-01Added 108 answers

Taking the clockwise direction as negative, the velocity
v=R
w=(0.11)
b) The force of friction Ffr=μkmg
The accelerationproduced m a=μmg 0r a=μ kg
c) The angular acceleration a=tI=μ mgR2mR25a=5μg2R
d) The angular speed of the ball increases from 0 to w according to theequation
w=at
But w=v/R thus, wehave v/R=5μgt2R 0r t=2v5μg
e) The length of skidding of theball
D x=v t12μgt2
f) The linear speed of the ball V=vμgt

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