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asked 2020-11-09

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2020-11-10
Total electric potential at
\(\displaystyle{P}={k}{\left({\frac{{+{7}{q}}}{{{5}}}}\cdot{\frac{{{d}}}{{{2}}}}\right)}+{k}{\left({\frac{{-{5}{q}}}{{{5}}}}\cdot{\frac{{{d}}}{{{2}}}}\right)}+{k}{\left({\frac{{+{5}{q}}}{{{5}}}}\cdot{\frac{{{d}}}{{{2}}}}\right)}+{k}{\left({\frac{{+{7}{q}}}{{{5}}}}\cdot{\frac{{{d}}}{{{2}}}}\right)}+{k}{\left({\frac{{+{3}{q}}}{{{\frac{{{d}}}{{{2}}}}}}}\right)}+{k}{\left({\frac{{-{3}{q}}}{{{\frac{{{d}}}{{{2}}}}}}}\right)}\)
\(\displaystyle={2}{k}{\left({\frac{{+{7}{q}}}{{{5}}}}\cdot{\frac{{{d}}}{{{2}}}}\right)}\) volts
\(\displaystyle{q}={8.5}\cdot{10}^{{-{6}}}\ {C}\)
\(\displaystyle{d}={0.18}\ {m}\)
\(\displaystyle{k}={9}\cdot{10}^{{9}}{N}\frac{{m}^{{2}}}{{C}}\)
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