A transverse sine wave with an amplitude of 2.50 mm and a wavelength of 1.80 m travels from left to right along a long, horizontal stretched string with a speed of 36.0 m/s. Take the origin at the left end of the undisturbed string. At time t = 0 the left end of the string has its maximum upward displacement. What is y (t) for a particle 1.35 m to the right of the origin? Round all numeric coefficients to exactly three significant figures.

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diskusje5 · Accepted Answer

Step 1This may be able to help you get a head start on the issue.:if the point on the most left side has the greatest upward deflection at time zero, it may most easily be modelled as a cosine function, of formy(t)=Acos⁡(Bt+C)where A is the amplitude, 2.5mm (A=0.0025), B is the frequency of the function and C is the phase displacement.Step 2Using&amp;nbsp;v=fλ, you can find that the frequency of the wave is 20 Hz, that is, 20 complete cycles of the wave form in 1 second(B=20). The period is 0.05 sec (50 ms).The phase shift is calculated by moving the curve forward or back sufficient to observe the point 1.35m from the left or right hand point. 1.35m is 0.75 times the wave length.You can see from a quick sketch that this point is zero and has an upward slope. The sine wave without any phase displacement is what we are left with..y(t)=0.0025sin⁡(20t)

A transverse sine wave with an amplitude of 2.50 mm and a wavelength of 1.80 m travels from left to right along a long, horizontal stretched string wi

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