The value of good wine increases with age. Thus,if you are a wine dealer, you have the problem of deciding whetherto sell your wine now, at a price of

illusiia

illusiia

Answered question

2020-12-09

The value of good wine increases with age. Thus,if you are a wine dealer, you have the problem of deciding whetherto sell your wine now, at a price of P a bottle, or to sell itlater at a higher price. Suppose you know that the amount awine-drinker is willing to pay for a bottle of this wine tyears from now is :
P(1+20?t)
Assuming continuous compounding and a prevailing interest rateof 5% per year, when is the best time to sell your wine?

Answer & Explanation

Bentley Leach

Bentley Leach

Skilled2020-12-10Added 109 answers

If the dealer sold the bottle now for $P, and invested that $p at 5%, the return would be, R1=P(1.05)t, which means that after t years, the dealer would have $P×1.05t.

If the dealer instead waited t years to sell then he would get, R2=$P(1+20rt(t)).

To find the value of t which would make both returns equal,set R1=R2.

P1.05t=P(1+20rt(t))

1.05t=1+20rt(t)

1+20rt(t)1.05t=0

There are a few ways to solve this. Newton-Raphson method, on your calculator may be able to do it, or some equation-solving software (eg DeadLine)

Anyway, the answer is:

t=109.6yrs

From the graph you can see that, for the first 109 yrs 8 months, the dealer will get a greater return by waiting for the buyer to buy, rather than investing $P at 5% interest compounded annually.

Since the dealer is unlikely to last for another 109 yrs and 8 months, then he can sell at any time he wishes for a greater return.

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