A 5cm radius isolated conducting sphere ischarged so its potential is -100V, relative to the potential faraway. What is the charge density on its surface?
Ava-May Nelson
Answered question
2020-11-23
Answer & Explanation
crocolylec
Skilled2020-11-24Added 100 answers
Given that
The radius of the conducting sphere is(r)
The potential is(V) = -100V
We know that the constant 1/4??o=9*109Nm2/C2
We know that
The potential (V) =1/4o.(q/r)
Now find charge from the above formula
The surface charge density is given by (?) = q/4r2
Now substitute all the above values you get the required answer i hope this may helps you
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