A force acting on a particle moving in the xy plane is given by F=(2yi+x^2j)N

Bevan Mcdonald

Bevan Mcdonald

Answered question

2021-01-06

A force acting upon a particle moving in the xy plane is given by  F=(2yi+x2j)N, where x and y are in meters. As shown in Figure, the particle travels from the origin to a final place with the coordinates x=4.65 m and y=4.65 m.
image
a) Calculate the work done by F along OAC
b) Calculate the work done by F along OBC
c) Calculate the work done by F along OC
d) Is F conservative or nonconservative?

Answer & Explanation

estenutC

estenutC

Skilled2021-01-07Added 81 answers

From the graph
a) The work done along OAC is W=(12)xy=12(4.65)(4.65)=10.8 J
b) The work done along OBC W=12xy=12(4.65)(4.65)=10.8 J
c) The work done along OC is W=Fs=(2yi+x2j)(4.65i+4.65j)=(24.654.65+(4.65)3=143.78 J
d) So, it is a nonconservative force

Do you have a similar question?

Recalculate according to your conditions!

New Questions in High School

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?