Question

An open vessel containing (a) water, (b)benzene, (c) mercury stands in a laboratory measuring 6.0m x 5.3m x3.2m at 25 degrees. What mass of each susbstance will be found inthe air if there is no ventilation? (The vapour pressures are (a)3.2kPa, (b) 14 kPa, (c) 0.23 Pa.)

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asked 2021-01-05
An open vessel containing (a) water, (b)benzene, (c) mercury stands in a laboratory measuring 6.0m x 5.3m x3.2m at 25 degrees. What mass of each susbstance will be found inthe air if there is no ventilation? (The vapour pressures are (a)3.2kPa, (b) 14 kPa, (c) 0.23 Pa.)

Answers (1)

2021-01-06
We know 1atm = 101.325kPa
a) \(\displaystyle{3.25}{k}{P}{a}\times{1}{a}{t}\frac{{m}}{{101.325}}{k}{P}{a}={0.0320}{a}{t}{m}\) and we know 1atm = 760torr at 250
C vapor pressure of wateris 23.76torr = 23.76torr*1atm/760 torr = 0.0312atm
H2O= (0.0320 - 0.0312) atm =0.0008atm
PV = nRT
Calculate \(\displaystyle{V}={6.0}{m}\times{5.3}{m}\times{3.2}{m}\) and convert into L 1m3= 1000L
After that plug the respective values to getn(moles)
n = mass(g) / molar mass(g/mol)
we know n and molar mass so we calculatethe mass(g)
Similarly for other two
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