A 0.50 kg ball that is tied to the end of a 1.1 m light cord is revolved in a horizontal planewith

Harlen Pritchard 2020-11-05 Answered

A 0.50 kg ball that is tied to the end of a 1.1 m light cord is revolved in a horizontal planewith the cord making a 30 angle, with the vertical.
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a) Determine the ball speed.
b) If, instead, the ball is revolved so that its speed is 4.0 m/s,what angle does the cord make with the vertical?
c) If the cord can withstand a maximum tension of 9.1 N, what is the highest speed at which the ballcan move?

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Expert Answer

Aubree Mcintyre
Answered 2020-11-06 Author has 73 answers
Answers:
Part a)
mv2r=Tsin(θ)
mg=Tcos(θ)
tan(θ)=v2rg
v2=rgtan(θ)
but
r=htan(θ)
v2=hg(tan(θ))2
v2=1.1×9.8×(tan(30))2
=3.5933
v=1.8956ms
Part(b):
v2=hg(tan(θ))2
(tan(θ))2=421.1×9.8
θ=50.62 degrees
Part (c):
If the cord can withstand a maximum tension of T=9.1N then the speed is given by
mv2r=Tsin(θ)
v2=rTsin(θ}{m}
=Thtan(θ)sin(θ)m
=9.1×1.1×tan(30)sin(30)0.5kg
v=2.404ms
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