What is a quadratic equation in standard form with rational coefficients that has a root of 5 + 4i?

arenceabigns 2021-01-06 Answered
What is a quadratic equation in standard form with rational coefficients that has a root of 5 + 4i?
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rogreenhoxa8
Answered 2021-01-07 Author has 109 answers
Complex zeros come in conjugate pairs so we know that 5-4i is a zero given that 5+4i is a zero.
If a is zero of a polynomial function, then x-a is one of its factor.
So, the quadratic equation is:
y=a(x(5+4i))(x(54i))
By expanding
y=a[x2(54i)x(5+4i)x+(5+4i)(54i)] y=a[x25x+4ix5x4ix+(2516i2)] y=a[x210x+(2516(1))] y=a(x210x+41) For simplicity, leta=1: y=x210+41
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