A proton is moving parallel to a uniform electric field. The electric field accelerates the proton and increases its linear momentum to 5.0 x 10^-23 kg x m/s from 1.5 x 10^-23 m/s in a time of 6.3 x 10^-6 s. What is the magnitude of the electric field?

Question

A proton is moving parallel to a uniform electric field. The electric field accelerates the proton and increases its linear momentum to 5.0 x 10^-23 kg x m/s from 1.5 x 10^-23 m/s in a time of 6.3 x 10^-6 s. What is the magnitude of the electric field?

Carol Gates 2021-02-09 Answered

A proton is moving parallel to a uniform electric field. The electric field accelerates the proton and increases its linear momentum to $5.0 \times 10^{- 23} k g x m / s$ from $1.5 \times 10^{- 23} m / s$ in a time of 6.3 x 10^-6 s. What is the magnitude of the electric field?

Ask Expert 2 See Answers

You can still ask an expert for help

Expert Answer

Leonard Stokes

Answered 2021-02-10 Author has 98 answers

F =qE

F △ t = △ p

q E = \frac{△ p}{△ t}

E = \frac{△ p}{q △ t}

This is helpful 30

Jeffrey Jordon

Answered 2021-09-30 Author has 2027 answers

Given that the initial momentum is $p_{1} = 1.50 * 10^{- 23} k g \times m / s$
the final momentum is $p_{2} = 5.00 * 10^{- 23} k g \times m / s$
the time taken is $t = 6.3 \times 10^{- 6}$ s.
-------------------------------------------------------------------------------
The charge of the proton is $q = 1.602 \times 10^{- 19}$ C

The force related with momentum is
$F = \frac{(P_{2} - P_{1})}{t}$
$E_{q} = \frac{(P_{2} - P_{1})}{t}$ (since $F = E_{q}$ )
SO electric field ,
$E = \frac{(P_{2} - P_{1})}{t \times q}$
$= \frac{(5 - 1.5) \times 10^{- 23}}{[1.602 \times 10^{- 19} \times 6.3 \times 10^{- 6}]}$
= $0.3468 \times 10^{2}$
= 34.68 N/C

This is helpful 90

Relevant Questions

asked 2021-02-04

A small rock with mass 0.12 kg is fastened to a massless string with length 0.80 m to form a pendulum. The pendulum is swinging so as to make a maximum angle of 45 with the vertical. Air Resistance is negligible.
a) What is the speed of the rock when the string passesthrough the vertical position?
b) What is the tension in the string when it makes an angle of 45 with the vertical?
c) What is the tension in the string as it passes through the vertical?

See answers (1)

asked 2021-02-20

An adventurous archaeologist crosses between two rock cliffs by slowly going hand-over-hand along a rope stretched between the cliffs. He stops to rest at the middle of the rope (Fig. 1) The rope will break if the tension in it exceeds $4.50 \cdot 10^{4}$ N and our hero's mass is 86.5 kg.

Figure 1 a) If the angle $θ$ is ${13.0}^{\circ}$ , find the tension iin the rope.

b) What is the smallest value the angle $θ$ can have if the rope is not to break?

See answers (1)

asked 2020-12-01

Here is problem, please help

See answers (1)

asked 2021-02-18

In an industrial cooling process, water is circulated through a system. If the water is pumped with a speed of 0.45 m/s under a pressure of 400 torr from the first floor through a 6.0-cm diameter pipe, what will be the pressure on the next floor 4.0 m above in a pipe with a diameter of 2.0 cm?

See answers (1)

asked 2022-01-15

a) Calculate the number of cells in a hummingbird assuming the mass of an average cell is ten times the mass of a bacterium. The mass of a hummingbird is of the order of