\(\displaystyle{F}={m}{a}={m}?{\frac{{{v}}}{{{t}}}}={\frac{{{73}\times{13}}}{{{7.1}}}}={134}{N}\)

\(\displaystyle{F}={m}{a}={m}?{\frac{{{v}}}{{{t}}}}={73}\times{\frac{{{13}}}{{{24}}}}={39.5}{N}\)

2. v initial = 0 v final = 13 m/s t= 7.1s

v=vo +at

partb. vo= 13 vf=0 t=24s 13=7.1a

usethe same process as in part a and note that your a= 1.83m/s2 accelerationwill be negative, giving you a negative netforce

?F=ma

F=(73 kg)( 1.83 m/s2)

F=133.59 N

\(\displaystyle{F}={m}{a}={m}?{\frac{{{v}}}{{{t}}}}={73}\times{\frac{{{13}}}{{{24}}}}={39.5}{N}\)

2. v initial = 0 v final = 13 m/s t= 7.1s

v=vo +at

partb. vo= 13 vf=0 t=24s 13=7.1a

usethe same process as in part a and note that your a= 1.83m/s2 accelerationwill be negative, giving you a negative netforce

?F=ma

F=(73 kg)( 1.83 m/s2)

F=133.59 N