A 15-g bullet strikes and becomes embedded in a 1.10-kg block of wood placed on a horizontal surface just in front of the gun. If the coefficient of friction between the block and the surface is 0.25,and the impact drives the block a distance of 9.5 m before it comes to rest, what was the muzzle speed of the bullet. The muzzle speed sounds like it's the bullet's stopping velocity. I got&nbsp;−5.0∗104&nbsp;for that, but the magnitude seems a little high.

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A 15-g bullet strikes and becomes embedded in a 1.10-kg block of wood placed on a horizontal surface just in front of the gun. If the coefficient of friction between the block and the surface is 0.25,and the impact drives the block a distance of 9.5 m before it comes to rest, what was the muzzle speed of the bullet. The muzzle speed sounds like it&#039;s the bullet&#039;s stopping velocity. I got&amp;nbsp;−5.0∗104&amp;nbsp;for that, but the magnitude seems a little high.

krolaniaN · Accepted Answer

There is a small round-off error in Anonymous.. The correct answer is 507.158 m/s, but to three significant figures, both responses agree.mU+0=(M+m)V&amp;nbsp;V=mM+mU&amp;nbsp;Work-energy theorem:&amp;nbsp;W=△KE&amp;nbsp;−frS=M+m2△v2&amp;nbsp;−μ(M+m)gS=M+m2△(0−V2)&amp;nbsp;2μgS=V2=(mM+mU)2&amp;nbsp;U=M+mm2μgs

A 15-g bullet strikes and becomes embedded in a 1.10-kg blockof wood placed on a horizontal surface just in front of thegun. If the coefficient of fri

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