If cotθ=−3 and secθ<0
Expert Community at Your Service
Solve your problem for the price of one coffee
Given that cotθ=−3<0 and secθ then θ is in QII so sinθ>0.
since cotθ=−3=−31 we can let adj =3 and opp =1
Find the point on the line y=5x+3 that is closet to the origin.
See answers (1)
Ask your question. Get your
answer. Easy as that
Challenge In △ABC,m∠B is one-third the m∠A and m∠C is 37 less than the m∠A.. What are the measures of the angles of △ABC?
Find the remaining angles for △ABC. m∠B=30∘andm∠A=12m∠C
m∠A=√∘ and m∠C=√∘
Get answers within minutes and finish your homework faster
Dont have an account?
Create a free account to see answers
Already have an account?