If cotθ=−3 and secθ<0 Find sinθ
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Given that cotθ=−3<0 and secθ then θ is in QII so sinθ>0. since cotθ=−3=−31 we can let adj =3 and opp =1 opp2+adj2=hyp2 (1)2+(3)2=hyp21+3=hyp2 4=hyp2 hyp=2 So, sinθ=opphyp since sinθ>0 sinθ=12
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