A ski gondola is connected to the top of a hill by a steelcable of length 620m and diameter 1.5cm. As teh gondola comes tothe end of its run, it bumps

CMIIh

CMIIh

Answered question

2020-10-26

A ski gondola is connected to the top of a hill by a steelcable of length 620m and diameter 1.5cm. As teh gondola comes tothe end of its run, it bumps into the terminal and sends a wavepulse along the cable. It is observed that it took 16 seconds forthe pulse to return. a) What is the speed of the pulse? b)What isthe tension in the cable?
I believe to find the speed of the pulse all I ahve to do is V=distancetravelled timetake (V=Xt) so it would equal 77.5 m/s
To find tension i would use V2=FT÷(m÷L)
After manipulating it I get FT=V2×(mL)
i know V=77.5 and L = 620 but i dont know how to find m.Please help! I dont even know if I did the rest of the problemright please help as soon as possible. Thanks

Answer & Explanation

svartmaleJ

svartmaleJ

Skilled2020-10-27Added 92 answers

A ski gondola is connected to the top of a hill by a steelcable of length 620m and diameter 1.5cm. As teh gondola comes tothe end of its run, it bumps into the terminal and sends a wavepulse along the cable. It is observed that it took 16 seconds forthe pulse to return. a) What is the speed of the pulse? b)What isthe tension in the cable?
I believe to find the speed of the pulse all I ahve to dois ν=FTmL
ν=Ep
) so it would equal 77.5 m/s
To find tension i would use 200×109
After manipulating it I get
πr2l i know V=77.5 and L = 620 but i dont know how to find m.
Please help! I donteven know if I did the rest of the problem right please help assoon as possible
You can find the mass of thecable by this way
'm ' = volume of cable *
density ofcable
= (pd2×L4×(7860kgm3))=861.2kg

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