Two straight conducting rails form a right angle where their ends are joined.

lwfrgin

lwfrgin

Answered question

2021-03-09

Two straight conducting rails form a right angle where their ends are joined. A conducting bar in contact with the rails starts at the vertex at time t = 0 and moves with a constant velocity of 6.40 m/s along them, as shown in Figure. A magnetic field with B = 0.350 T is directed out of the page.
image
a) Calculate the flux through the triangle formed by the bars at t=3.80 s
b) Calculate the emf around the triangle at that time.
c) If we write the emf as =atn, where a and n are constants, what is the value of n?

Answer & Explanation

Malena

Malena

Skilled2021-03-10Added 83 answers

a) A=12(base)(height)=12(2vt)(vt)=v2t2
Uniform B = 0.350 T, magnetic flux is then ϕB=BA=(0.350)(6.40ms)2t2=14.336t2
Plugging in t= 3.80 s we find ϕB=207 Wb
b) The magnitude of the emf is the Faraday's law:
E=dϕBdt=14.3dt2dt=28.6t
At t=3.80 s, this yields
e=108.7 V
c) Calculation in b shows that n=1

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